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  1. Prepare
  2. Python
  3. Sets
  4. Set .union() Operation
  5. Discussions

Set .union() Operation

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  • maluisamrok
     + 0 comments
    n=int(input())
english = set(list(map(int, input().split())))
b= int(input())
french= set(list(map(int, input().split())))
both = english.union(french)

print(len(both))

  • s_fadel
     + 0 comments
    n = int(input())
english = set(map(int, input().split()))

b = int(input())
french = set(map(int, input().split()))


diff = english.union(french)
print(len(diff))

  • chathurirasanja1
     + 0 comments
    n = int(input())
eng = set(map(int, input().split()))
b = int(input())
fre = set(map(int, input().split()))

print(len(eng | fre))

  • trinoyjitkalita
     + 0 comments

    a = int(input()) b = set(map(int, input().split())) c = int(input()) d = set(map(int, input().split()))

    e = b.union(d) count=0 for i in range(len(e)): count=count+1

    print(count)

  • saijyothi969
     + 0 comments

    I am giving explanation to my code. First I have used n=int(input()) => for the number of students are in the english news paper and then I am setting this to the set method which is a= set(input().split()) as the numbers need to be split and I am repeating the same procedure for french paper. Later, we need to do the union method and print the length. n = int(input()) n= set(input().split()) b = int(input()) e= set(input().split()) r = n.union(e) print(len(r))

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