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  1. Prepare
  2. Python
  3. Sets
  4. Set .discard(), .remove() & .pop()
  5. Discussions

Set .discard(), .remove() & .pop()

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1021 Discussions

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  • sunidhidivekar21
     + 0 comments

    For pypy3

    n = int(input()) s = set(map(int, input().split()))

    n_2 = int(input())

    for i in range(n_2): string = input() try: if "remove" in string or "discard" in string: command, value = string.split() value = int(value) if command == "remove": s.remove(value) elif command == "discard": s.discard(value)

        else:
        r=list(s)
        s=set(r[1:])
except KeyError:
    pass

    print(sum(s))

  • kshitizyaksh
     + 0 comments

    Use Python3 instead of pypy3 to get this correct

  • sefamutlucu
     + 0 comments
    n = int(input())
s = set(map(int, input().split()))
cn = int(input())

for i in range(cn):
    command, *number = input().split()
    
    if number:
        number = int(number[0])
        eval(f"s.{command}(number)")
    
    else:
        eval(f"s.{command}()")

print(sum(s))

  • imam_alfaridzi
     + 0 comments

    Here's my code:

    n, s = int(input()), set(map(int, input().split()))
for i in range(int(input())):
    f, _, v = input().partition(' ')
    if not hasattr(set, f):
        continue
    getattr(s, f)(int(v)) if v else getattr(s, f)()
print(sum(s))

  • asamad_awais1
     + 0 comments
    n = int(input())
s = set(map(int, input().split()))

n_2 = int(input())

for i in range(n_2):
    string = input()
    if "remove" in string or "discard" in string:
        command, value = string.split()
        value = int(value)
        if command == "remove":
            s.remove(value)
        elif command == "discard":
            s.discard(value)

    else:
        s.pop()
print(sum(s))