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  1. Prepare
  2. Python
  3. Sets
  4. Check Subset
  5. Discussions

Check Subset

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905 Discussions

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  • jkarakus
     + 0 comments

    Solution without using .issubset()

    case = int(input())

for i in range(case):
    numA = int(input())
    setA = set(list(map(int, input().split())))
    
    numB = int(input())
    setB = set(list(map(int, input().split())))
    
    print(len(setA - setB)==0)

  • sefamutlucu
     + 0 comments
    t = int(input())

for i in range(t):
    nA = input()
    setA = set(input().split())

    nB = input()
    setB = set(input().split())
    
    print(setA.issubset(setB))

  • imam_alfaridzi
     + 0 comments

    Here's my code:

    for _ in range(int(input())):
    al = int(input())
    a = set(list(map(int, input().split()))[:al])
    bl = int(input())
    b = set(list(map(int, input().split()))[:bl])
    print(a.issubset(b))

  • yvonnesunny
     + 0 comments
    print(b_set.intersection(a_set)==a_set)

  • syahrulmahar92
     + 0 comments

    T = int(input()) for i in range(T): A = int(input()) A_el = set(map(int, input().split())) B = int(input()) B_el = set(map(int, input().split())) print(A_el.difference(B_el) == set())