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  1. Prepare
  2. Python
  3. Sets
  4. Check Subset
  5. Discussions

Check Subset

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recency

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926 Discussions

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  • mohammedsayed261
     + 0 comments

    T = int(input()) result = list([]) for i in range(T): n1 = int(input()) A = set(list(map(int, input().split()))[:n1]) n2 = int(input()) B = set(list(map(int, input().split()))[:n2])

    if A.issubset(B):
    result.append(True)
else:
    result.append(False)

    for i in result: print(i)

  • Benjii
     + 0 comments

    can be done by checking on subset length:

    n = int(input())

for i in range(0, n):
    n_a, a = int(input()), set(input().split())
    n_b, b = int(input()), set(input().split())
    subset = a - b
    print(len(subset) == 0)

  • rahuluk9632
     + 0 comments
    from collections import Counter

n = int(input())
a = Counter(sorted(list(map(int, input().strip().split()))))
b = [i for i,j in a.items() if j<n]
print(*b)``

  • anw_g01
     + 0 comments
    T = int(input())
for _ in range(T):
    _ = int(input())
    A = set(map(int, input().split()))
    _ = int(input())
    B = set(map(int, input().split()))
    print(A.issubset(B))

  • vjb08
     + 0 comments

    simple logic

    t = int(input()) i = 0 while i in range(t):
    set_a = int(input()) set_a_list = set(list(input().split())) set_b = int(input()) set_b_list = set(list(input().split())) print(set_a_list.issubset(set_b_list)) i += 1