We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Sets
  4. Check Strict Superset
  5. Discussions

Check Strict Superset

Sort by

recency

|

1133 Discussions

|

  • akash_prajapati6
     + 0 comments
    seta = list(map(int, input().split()))
num = int(input())
result=bool(True)
for _ in range(num):
    setx = list(map(int, input().split()))
    for i in setx:
        if(i in seta):
            continue
        else:
            result = bool(False)
            break
print(result)

  • vsowmika2004
     + 0 comments
    a=set(map(int,input().split()))
n=int(input())
count=0
for i in range(n):
    s=set(map(int,input().split()))
    if(s-a==set() and len(s)<len(a)):
        count+=1
if count==n:
    print("True")
else:
    print('False')

  • harsh_k_arora
     + 1 comment

    ` _set = set(map(int, input().split()))

    print(all([set(map(int, input().split())) <= _set for _ in range(int(input()))])) `

  • nidhipawankumar
     + 0 comments

    set_a = set(map(int, input().split())) n = int(input())

    for _ in range(n): set_n = set(map(int, input().split()))

    # If set_a is not a strict superset of set_n, print False and break
if not set_a > set_n:  # This checks if set_a is a strict superset
    print(False)
    break

    else: # If set_a is a strict superset of all sets, print True print(True)

  • [deleted]Challenge Author     + 0 comments

    For Python3

    A = set(input().split())
n = int(input())
for i in range(n):
    s = set(input().split())
    
    if(len(s) == len(A)):
        print(False)
        break
    elif(not A.issuperset(s)):
        print(False)
        break
else:
    print(True)