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Printing Pattern Using Loops
Printing Pattern Using Loops
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int t=0,s=0;
simple and easy answer
takes the minimum out of i,j,size-i-1 and size-j-1, where size is 2n-1
core component of this code: for(int x=0;x=n;x--) { for(int y=2*(n-1)-z;y>=z;y--){ a[x][y]=n-z; a[y][x]=n-z; } z++;}
include
void main( ) { int n; printf("Give input"); scanf("%i",&n); for(int i=1; i <= 2*n-1;i++) { int k=1; for(int j=1;j <= 2*n-1; j++) { for(int m=1;mi) k --; if(j>=2*n-i+1) k --; break; } printf("%i ",n-k+1); } printf("\n"); } }