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simple is best
cout << left << nouppercase << hex << showbase << (long long)A << endl;
IIt helped me, Thank you so much.
Sicne they have included iomanip
The lines cout.precision(); cout<< defaultfloat;
Bascially resets the iomanipulaton we did in cout , so that it wont be taken into consideration for the next iteration of the loop : )
Rounding up the second input of each entry of three doubles is not occuring consistently. In test case two, the twelfth entry of three doubles, the second entry, 963.015, the expected output is __+963.01 which is not rounded up. However, then, in the 29th entry of three doubles, the second double entry is 218.895 with the expected output of __+218.90 which is rounded up. This shoudl be corrected or clarified.
Can I sare a issue similer like this here?