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  1. Prepare
  2. Mathematics
  3. Geometry
  4. Points on a Rectangle
  5. Discussions

Points on a Rectangle

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7 Discussions

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  • denis_plaj1
     + 0 comments

    def solve(coordinates):

    d = dict(coordinates)

y = d.values()
x = d.keys()

min_x = min(x)
max_x = max(x)
min_y = min(y)
max_y = max(y)

ret = "YES"
for el in coordinates:
    if (el[0] > min_x) & (el[0] < max_x) & (el[1] > min_y) & (el[1] < max_y):
        ret = "NO"
        break
return ret

  • devarshiporwal42
     + 1 comment
    #include <stdio.h>
int main ()
{
    int i, q;
    scanf("%d", &q);
    for (i = 1; i <= q; i++)
    {
        int j, n, minx, maxx, miny, maxy, count = 0;
        scanf("%d", &n);
        int x[n], y[n];
        for (j = 0; j < n; j++)
        {
            scanf("%d %d", &x[j], &y[j]);
        }
        minx = x[0], maxx = x[0], miny = y[0], maxy = y[0];
        for (j = 1; j < n; j++)
        {
            if (x[j] < minx)
            {
                minx = x[j];
            }
            if (x[j] > maxx)
            {
                maxx = x[j];
            }
            if (y[j] < miny)
            {
                miny = y[j];
            }
            if (y[j] > maxy)
            {
                maxy = y[j];
            }
        }
        for (j = 0; j < n; j++)
        {
            if (x[j] > minx && x[j] < maxx && y[j] > miny && y[j] < maxy)
            {
                count++;
            }
        }
        if (count > 0)
        {
            printf("NO\n");
        }
        else
        {
            printf("YES\n");
        }
    }
}

  • bradleywaddell17
     + 0 comments

    Another approach: if the x coordinate is in [max_x, min_x] or the y_coordinate is in [max_y, min_y] for every point in the set, then it is a rectangle parallel to the axes because otherwise there would either be a point outside or inside the rectangle

  • killbill143
     + 0 comments

    include

    include

    include

    include

    int main() { /* Enter your code here. Read input from STDIN. Print output to STDOUT */ int t; scanf("%d",&t); while(t--) { int n,x[10],y[10],i,minx=10000,maxx=-10000,miny=10000,maxy=-10000; int flag=0; scanf("%d",&n); for(i=0;i=x[i]) minx=x[i]; if(maxx<=x[i]) maxx=x[i]; if(miny>=y[i]) miny=y[i]; if(maxy<=y[i]) maxy=y[i]; } //printf("%d\t%d\t%d\t%d\n",minx,maxx,miny,maxy); for(i=0;i 

        }
    if(flag==1)
        printf("NO");
    else
        printf("YES");
    printf("\n");
}
return 0;

    }

  • xdavidliu
     + 0 comments

    note that the question only asks for axis parallel rectangles, e.g. sides are either vertical or horizontal lines. Without this restriction, the problem would be significantly more nontrivial!