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  1. Prepare
  2. Mathematics
  3. Geometry
  4. Points On a Line
  5. Discussions

Points On a Line

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47 Discussions

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  • trupti29
     + 0 comments

    !/bin/python3

    import math import os import random import re import sys

    if name == 'main': n = int(input()) H = [] V = []

    for n_itr in range(n):
    xy = input().split()

    x = int(xy[0])

    y = int(xy[1])

    H.append(xy[0])
    V.append(xy[1])
setH = set(H)
setV = set(V)
if len(setH) == 1 or len(setV) == 1:
    print("YES")
else:
    print("NO")

  • Zerazera
     + 0 comments

    My javascript solution (two liner, could easily be one):

    function main() {
    const points = Array(+readLine()).fill().map(_ => readLine().split(' ').map(x => +x));
    console.log([0, 1].some(x => points.every((y, _, arr) => y[x] == arr[0][x])) ? 'YES' : 'NO');
}

  • klu2300040248
     + 1 comment

    int main() { int n,x,y,x1,y1,cx=0,cy=0,flag=0,num; scanf("%d",&n); num=n; while(n--) { if(flag==0) { scanf("%d%d",&x,&y); x1=x; y1=y; flag=1; } else if(flag==1) { scanf("%d%d",&x,&y); if(x==x1) { cx++; } else if(y==y1) { cy++; } } } if(cx==num-1 || cy==num-1) { printf("YES"); } else { printf("NO"); } }

  • hoangziet22
     + 0 comments
    x = []
y = []
n = int(input())
for i in range(n):
    xy = input().split()
    x.append(xy[0])
    y.append(xy[1])
print ("YES" if (len(set(x)) == 1 or len(set(y)) == 1 ) else "NO")

  • brewjunk
     + 0 comments
    import math
import os
import random
import re
import sys

def line(arr_x,arr_y):
    if len(set(arr_x)) == 1:
        return "YES"
    elif len(set(arr_y)) == 1:
        return "YES"
    else:
        return "NO"
    
if __name__ == '__main__':
    n = int(input())
    arr_x = []
    arr_y = []
    for n_itr in range(n):
        xy = input().split()
        x = int(xy[0])
        y = int(xy[1])
        arr_x.append(x)
        arr_y.append(y)
    print(line(arr_x,arr_y))