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Plus Minus

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  • allisonsara65
     + 0 comments

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  • mdhanifkhan116
     + 0 comments

    Language: JAVA 15

    In this problem We have to print the ratios of positive, negative and zero values with 6 digits after the decimal. To solve this problem I used printf() with format specifier

        public static void plusMinus(List<Integer> arr) {
    
    double positive=0;
    double negative=0;
    double zero=0;

    for(int i : arr){
        if(i>0){
            positive++;
        }
        else if(i<0){
            negative++;
        }
        else {
            zero++;
        }
        
    }
    
    System.out.printf("%.6f", positive/arr.size());
    System.out.println();
    System.out.printf("%.6f", negative/arr.size());
    System.out.println();
    System.out.printf("%.6f", zero/arr.size());
    
    }

  • ubirata_lucas03
     + 0 comments
        public static void plusMinus(List<int> arr)
    {
        int p = 0, n = 0, z = 0, l = arr.Count;
        foreach(int el in arr)
        {
            if(el > 0)
                p++;
            else if(el < 0)
                n++;
            else if(el == 0)
                z++;
        };
        
        decimal pD = p, nD = n, zD = z;
        
        Console.WriteLine((pD/l).ToString("F6"));
        Console.WriteLine((nD/l).ToString("F6"));
        Console.WriteLine((zD/l).ToString("F6"));
    }

  • shriyabhat25
     + 0 comments

    ///Java Solution

    class Result { public static void plusMinus(List arr) { double countpos=0, countneg=0, countzero=0; double n=arr.size(); for(int i=0;i 0){ countpos++; } else if(arr.get(i) < 0){ countneg++; } else if(arr.get(i)==0){ countzero++; } }

     System.out.println(String.format("%.6f", countpos/n));
 System.out.println(String.format("%.6f", countneg/n));
 System.out.println(String.format("%.6f", countzero/n));

}

    }

  • nuemon20
     + 1 comment

    n = int(input().strip()) arr = [1 if int(temp)>0 else -1 if int(temp)<0 else 0 for temp in input().strip().split(' ') ] print("{0:.6f}".format(arr.count(1)/n)) print("{0:.6f}".format(arr.count(-1)/n)) print("{0:.6f}".format(arr.count(0)/n))