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  1. Prepare
  2. C
  3. Introduction
  4. Playing With Characters
  5. Discussions

Playing With Characters

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  • sheikhmohammeds2
     + 1 comment
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() 
{
    char ch;
    char s[24];
    char t[100];
    
    scanf("%c", &ch);
    scanf("%s", s);
    getchar();
    scanf("%[^\n]%*c", t);
    
    printf("%c\n", ch);
    printf("%s\n", s);
    printf("%s\n", t);
     
    return 0;
}

  • samarthrjain240
     + 0 comments
    #include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() 
{
    char ch;
    char s[24];
    char t[100];
    
    scanf("%c", &ch);
    scanf("%s", s);
    getchar();
    scanf("%[^\n]%*c", t);
    
    printf("%c\n", ch);
    printf("%s\n", s);
    printf("%s\n", t);
     
    return 0;
}

  • divyanshisahuds
     + 0 comments

    include

    include

    include

    include

    int main() {
    char ch,s[20],sen[100];

    scanf("%c\n",&ch);
scanf("%s\n",&s);
scanf("%[^\n]%*c",&sen);

printf("%c\n",ch);
printf("%s\n",s);
printf("%s\n",sen);


/* Enter your code here. Read input from STDIN. Print output to STDOUT */    
return 0;

    }

  • mdfazlerabbispo1
     + 0 comments

    In order to take a line as input, you can use scanf("%[^\n]%*c", s); where is defined as char s[MAX_LEN] where MAX_LEN is the maximum size of s. Here, [] is the scanset character. ^\n stands for taking input until a newline isn't encountered. Then, with this %*c, it reads the newline character and here, the used * indicates that this newline character is discarded. Note: The statement: scanf("%[^\n]%*c", s); will not work because the last statement will read a newline character,

    Can someone please explain these 2 lines to me? Don't they seem contradictory?

  • rishikeshkumar74
     + 0 comments

    int main() { printf("C\nLanguage \nWelcome To C!!");

    return 0;

    }