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recency

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  • + 0 comments

    I believe the main issue here is when we have passwords like this: [...,'aaaa' , 'aaaaaa',...]

    and loginAttempt like this: ...aaaaaaaaaa...

    We can find 'aaaa' + 'aaaa' but will remain 'aa' giving us a 'WRONG PASSWORD'. But, if we take 'aaaaaa' and then 'aaaa' we're gonna find a good answer.

  • + 0 comments

    return 'WRONG PASSWORD' if match == login: return res + match return passwordCracker, (passwords, login(minara.18_, res + match + ' ')

  • + 0 comments

    there are so many test cases and it seems working but most of them are failing because of time limit.

    `python

    for x in passwords: if x == loginAttempt[:len(x)]: # print(x) if x == loginAttempt: return x res = passwordCracker(passwords, loginAttempt[len(x):]) if res != 0 and 'WRONG PASSWORD' not in res: return x +' '+ res else: continue return 'WRONG PASSWORD'`

  • + 0 comments

    `if match is None: return 'WRONG PASSWORD' if match == login:hak_goswami return res + match

    Does not use up stack space since we use a trampoline

    return , (passwords, login[len(match):], res + match + ' ')

  • + 0 comments

    `if match is None: return 'WRONG PASSWORD' if match == login:hak_goswami return res + match

    Does not use up stack space since we use a trampoline

    return , (passwords, login[len(match):], res + match + ' ')