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  1. Prepare
  2. Algorithms
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  4. Pairs
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Pairs

  • krokiet
     + 1 comment

    Nice and easy this time! First time I post a solution here, because I'm stunned it worked at the very first time, wihtout any corrections (rare case;)

    Sort + caterpillar method.

    Java solution:

        public static int pairs(int k, List<Integer> arr) {
        Collections.sort(arr);
        int a = 0;
        int b = 1;
        int count = 0;
        while (a < b && b < arr.size()) {            
            int left = arr.get(a);
            int right = arr.get(b);
            int diff = right - left;
            if (diff == k) {
                count++;
                b++;
            } else if (diff > k) {
                a++;
                if (a==b) b++;
            } else {
                b++;
            }            
        }
				}
        return count;
    }