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  • + 0 comments

    Here is my solution in java, javascript, python, C, C++, Csharp HackerRank P-sequences Problem Solution

  • + 0 comments

    This problem is definitely easier than a fair number of the medium-rated DP problems. At least in this case it's obvious how to relate the desired solution to the solution to a smaller version of the problem. Sure, you need to figure out how to condense some of the sub-problems together so you can handle large P without running out of time or memory, but that's a much more straightforward problem.

  • + 0 comments

    Here is P-sequences problem solution - https://programs.programmingoneonone.com/2021/07/hackerrank-p-sequences-problem-solution.html

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    The algorithm is correct

    Still it will not work for very large number TestCases: 10,11,13,16,17 and 18. They exceed computational capacity of 53bit integers. Then, a special multiplication procedure will be needed in order to get the correct modulus without errors induced by those really really really really big numbers,,,,,

    function pSequences(n, p) {
        // Write your code here
        const MOD = 1000000000+7
        let root = parseInt(Math.sqrt(p)),
            last = root*2-((root*(root+1)>p)?2:1),
            qtty = [], val=[], calc=[], i=0, j=last, accum=0, size=last+1
        while (accum < p) calc[j--] = (accum += (val[i] = (qtty[i++] = (parseInt(p/parseInt(p/(accum+1))) - accum))))
        while(n-->=2) {
            let next = new Array(size)
            accum = 0
            for(i=0,j=last;i<=last;i++,j--) next[j] = (accum = (accum + (val[i] = ((qtty[i] * calc[i])%MOD)))%MOD)
            calc = next
        }
        return accum % MOD
    }
    
  • + 0 comments

    In JavaScript,

    var result=0;
        for(var i=1;i<=n;i++)
        {
            for(var j=1;j<=n;j++)
                {
                    if(i*j<=p)
                    {
                        result = result+1;
                    }
                }
        }
        return(result)
    		
    

    something is not working here.