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Can't be done for C, Might as well share my solution:
int compare(const void *a, const void b) {
return ((const int *)a - *(const int *)b);
}
int main() {
int cases;
scanf("%d", &cases);
for (int k = 0; k< cases; k++) {
int n;
scanf("%d", &n);
int *arr = malloc(n * sizeof(int));
int *final = malloc(n * sizeof(int));
for (int i = 0; i < n; i++) {
scanf("%d", &arr[i]);
}
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
qsort(arr, n, sizeof(int), compare);
for (int i = 0; i < n/2; i++) {
final[i] = arr[i];
final[n - i- 1] = arr[n/2+i];
}
final[n/2] = arr[n-1];
for (int i = 0; i < n; i++) {
printf("%d ", final[i]);
}
printf("\n");
}
return 0;
}
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Zig Zag Sequence
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Can't be done for C, Might as well share my solution:
int compare(const void *a, const void b) { return ((const int *)a - *(const int *)b); }
int main() { int cases; scanf("%d", &cases); for (int k = 0; k< cases; k++) { int n; scanf("%d", &n); int *arr = malloc(n * sizeof(int)); int *final = malloc(n * sizeof(int));
for (int i = 0; i < n; i++) { scanf("%d", &arr[i]); }
}