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2 weeks ago+ 0 comments

Most of the solutions im seeing are overdoing it or using packages (which imo is lowkey cheating LOL) but here's how i kept it beginner friendly 🫡 This also has a time complexity of O(1) iirc

def timeConversion(s):
    Hours = int(s[0:2]) #indexing the hours
    MinutesSeconds = s[2:8]
    AMPM = s[8:] #indexing the AM/PM
    
    if AMPM == "AM": #if its in the AM
        if Hours == 12:
            Hours = 0
    else: #when its NOT AM so it has to be PM
        if Hours != 12 : #while we're between the hours of 01pm - 11pm   
             Hours += 12 # add 12 to HH

    return f"{Hours:02}{MinutesSeconds}"

#f"{Hours:02} means that the HH should always have two integers, so if it were to be 7:42:41AM, that translates to 07:42:41 where it would be invalid without the 0
#MinutesSeconds just reserves the mm:ss since we're not touching that, so we can join it together via formatting

with comments because those are important

2 weeks ago+ 0 comments

include

using namespace std;

/* * Complete the 'timeConversion' function below. * * The function is expected to return a STRING. * The function accepts STRING s as parameter. */

string timeConversion(string s) { string period = s.substr(8, 2); // Extract AM or PM string hour_str = s.substr(0, 2); int hour = stoi(hour_str); string remaining = s.substr(2, 6); // Remaining part after hour (":MM:SS")

if (period == "AM") {
    if (hour == 12) {
        hour_str = "00";
    }
} else { // PM case
    if (hour != 12) {
        hour += 12;
        hour_str = to_string(hour);
    }
}

return hour_str + remaining;

}

int main() { ofstream fout(getenv("OUTPUT_PATH"));

string s;
getline(cin, s);

string result = timeConversion(s);

fout << result << "\n";

fout.close();

return 0;

}

3 weeks ago+ 0 comments

I used Java and tried to keep it simple and easy to read

public static String timeConversion(String s) {
       int hoursIn24 = 0;
       int hoursIn12 = 0;
       String result = s;
       
       hoursIn12 = Integer.parseInt(s.substring(0, 2));
       
       if (s.indexOf("AM") > 0){
           if (hoursIn12 == 12){
                result = "00" + s.substring(2, s.length() - 2);
           }
           else{
                result = s.substring(0, s.length() - 2);
           }
       }
       else{
         if (hoursIn12 == 12){
                result = s.substring(0, s.length() - 2);
         }
         else{
            hoursIn24 = 12 + hoursIn12;
            result = hoursIn24 + s.substring(2, s.length() - 2);
         }
       }
        return result;
    }

3 weeks ago+ 0 comments

GO

Easy to understand. Using "time" package

func timeConversion(s string) string {
    milLayout := "15:04:05"
    amPmLayout := "03:04:05PM"
    
    //handle err if u need
    t, _ := time.Parse(amPmLayout, s)
    
    return t.Format(milLayout)
}

algo

func timeConversion(s string) string {
    out := []rune(s)

    var isPm int
    if s[len(out)-2:] == "PM" {
        isPm = 1
    } else {
        isPm = 0
    }

    //handle err if u need
    hours, _ := strconv.Atoi(s[:2])
    if isPm == 1 && hours != 12 {
        hours += 12
    } else if isPm == 0 && hours == 12 {
        hours = 0
    }

    out[0] = rune(hours/10 + '0')
    out[1] = rune(hours%10 + '0')

    out = out[:len(out)-2]

    return string(out)
}

4 weeks ago+ 0 comments

def timeConversion(s): # Write your code here

hh, mm , ss = map(int, s[:-2].split(":"))
if s[-2:] == 'AM' and hh == 12:
    hh = 0
elif s[-2:] == 'PM' and hh != 12:
    hh+=12

return f"{hh:02}:{mm:02}:{ss:02}"

if name == 'main':

s = input()

result = timeConversion(s)

print(result)

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