my java solution: ` s= s.trim(); String timeMarker=s.substring(8); String originalTime = s.substring(0, 8); String[] originalTimeList= originalTime.split(":"); String hour = originalTimeList[0]; Integer hourInt = Integer.parseInt(hour); StringBuilder newTime = new StringBuilder();

if(timeMarker.equals("PM")){
    if(hourInt!=12){
        hourInt+=12;
        hour= String.valueOf(hourInt);
    }
}
else{
    if(hourInt==12){
        hour= "00";
    }
}

return newTime.append(String.valueOf(hour)).append(":")
.append(originalTimeList[1]).append(":")
.append(originalTimeList[2]).toString();

`

how can there be 12AM in a 12hr clock ?!? why the questions are like this?

My solution in JS

  var splitted = s.split(":")
    var time = splitted[splitted.length -1].substring(2)
    if(time == "PM") {
        var hour = parseInt(splitted[0])
        if(hour != "12") {
            hour = 12 + hour
        }
        return hour + ":" +splitted[1] +":" + splitted[2].substring(0,2)
    } else {
        if(splitted[0] == "12") {
            splitted[0] = "00"
        }
        return splitted[0] + ":" +splitted[1] +":" + splitted[2].substring(0,2)
    }

My Solution to that Problem:

def timeConversion(s): # Write your code here PM = { "01": "13", "02": "14","03": "15",
"04": "16", "05": "17", "06":"18", "07": "19", "08":"20", "09": "21", "10":"22", "11": "23", "12":"12"}

if s[-2] == "P":
    return PM[s[0:2]]+s[2:8] 

if s[-2] == "A" and s[0:2] == "12":
    return "00"+s[2:8]  
else:
    return s[0:8]  

My answer with Typescript, clearly

function timeConversion(str: string): string {
    const pad = (n: number) => n.toString().padStart(2, '0')

    // 0. read 12h
    let h = Number(str.substring(0, 2))
    let m = Number(str.substring(3, 5))
    let s = Number(str.substring(6, 8))
    let p = str.substring(8, 10)

    // 1. convert to 24h
    if (h == 12) h = 0
    if (p == 'PM') h += 12

    return `${pad(h)}:${pad(m)}:${pad(s)}`
}