We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Balanced Brackets
  2. Discussions

Balanced Brackets

  • wasifk308
     + 0 comments
    string isBalanced(string s) {
stack<char> stk;


for (int i = 0 ; i<s.length(); i++) 
{
if(!stk.empty())
{
char tp  =stk.top();

if( (tp == '{' && s[i] == '}')||(tp == '(' && s[i] == ')') ||( tp == '[' && s[i] == ']'))
{
stk.pop();

}else {
stk.push(s[i]);
}
}else {
stk.push(s[i]);

}

}