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  1. Sherlock and the Valid String
  2. Discussions

Sherlock and the Valid String

  • hank_ring
     + 0 comments
    from collections import Counter

def isValid(s):
    c = dict(sorted(Counter(Counter(s).values()).items()))
    return 'YES' if (len(c) == 1 or (len(c) == 2 and ((list(c.keys())[1] - list(c.keys())[0] == 1 and list(c.values())[1] == 1) or c.get(1) == 1))) else 'NO'