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  1. Pangrams
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Pangrams

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391 Discussions

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  • rishabhkumar9167
     + 0 comments
    r="".join(set(s.lower().replace(" ","")))
if len(r)==26:
        return 'pangram'
else:
        return 'not pangram'

  • bhupankarg2
     + 0 comments

    C++ Solution:

    string pangrams(string s)
{
    unordered_map<char, int> hMap;
    for(int i = 0; i < s.size(); i++)
    {
        hMap[s[i]] = 1;
    }

    for(int i = 0; i < 26; i++)
    {
        if(hMap['a' + i] == 0)
        {
            if(hMap['A' + i] == 0)
            {
                return "not pangram";
            }
        }
    }
    return "pangram";
}

  • cooldilcool
     + 0 comments

    C# solution

    public static string pangrams(string s)
{
    var lowerString = s.ToLower();
    char[] characters = lowerString.ToCharArray().Where(e => !string.IsNullOrEmpty(e.ToString().Trim())).ToArray();

    var charList = new List<char>();
    foreach(var character in characters)
    {
        if(charList.Any(e => e == character))
            continue;

        charList.Add(character);
    }

    if(charList.Count == 26)
        return "pangram";

    return "not pangram";
}

  • derekcommongrou1
     + 0 comments

    My solution for typescript:

    function pangrams(s: string): string {
    const ALPHABET_LENGTH = 26;
    const IS_PANGRAM = 'pangram';
    const IS_NOT_PANGRAM = 'not pangram'
    
    const isValidChar = (char: string): boolean => char !== ' ';
    
    return new Set(s
        .split('')
        .reduce((acc, char) => {
        return isValidChar(char) ? [...acc, char.toLowerCase()] : acc;
    }, [])).size === ALPHABET_LENGTH ? IS_PANGRAM : IS_NOT_PANGRAM;  
}

  • erlandohbs
     + 0 comments

    The simplest logic in python 

    def createAsciModel():
    a=97
    z=122
    res = []
    while(True):
        if(a>z):
            break
        res.append(a)
        a= a+1
    return res

def checkAsciModel(record, asciModel):
    for idx in range(len(asciModel)):
        asci = asciModel[idx]
        if asci == (ord(record)):
            return idx
def checkPangram(lowerCase, createAsciModel):
    asciModel = createAsciModel
    for records in lowerCase:
        idx = checkAsciModel(records,asciModel)
        if not idx and idx != 0:
            continue
        asciModel.pop(idx)
    return asciModel

def pangrams(s):
    # Write your code here
    lowerCase = s.lower()
    asciModel = createAsciModel()
    pangram = checkPangram(lowerCase, asciModel)
    if len(pangram)>0:
        return 'not pangram'
    return 'pangram'