def flippingBits(n): return n ^ 0xFFFFFFFF # XOR with a 32-bit mask

Java: long max32unsignedbit = (1L<<32)-1; return max32unsignedbit^n;

Javscript solution

• ~ Flips all the bits of the input n.
• >>> Ensures the result is treated as an unsigned 32-bit integer

function flippingBits(n) {
    // Write your code here
    return ~n  >>> 0
}

Python solution using XOR operator

def flippingBits(n):
    return  n ^ (2**32 - 1)

My Rust approach

fn flippingBits(n: i64) -> i64 {
    !(n as u32) as i64
}