Discussion on Mean, Var, and Std Challenge

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1 week ago+ 0 comments

import numpy

n=list(map(int,input().split()))
list1=[]
for _ in range(n[0]):
    list1.append(list(map(int,input().split())))
my_array = numpy.array(list1)
print(numpy.mean(my_array, axis = 1))
print(numpy.var(my_array, axis = 0))
print(round(numpy.std(my_array, axis = None),11))

4 weeks ago+ 0 comments

import numpy

n, m = map(int, input().split())

arr = numpy.array([list(map(int, input().split())) for _ in range(n)])

print(numpy.mean(arr, axis=1))
print(numpy.var(arr, axis=0))
print(round(numpy.std(arr, axis=None),11))

1 month ago+ 0 comments

import numpy as np

i = input()

n,m = list(map(int,i.split(' ')))

arr = np.array([list(map(int,input().split(' '))) for _ in range(n)])

print(np.mean(arr,axis=1)) print(np.var(arr,axis=0)) print(np.round(np.std(arr,axis=None),11))

2 months ago+ 0 comments

For Python3 Platform

It isn't mentioned to round off the standard deviation to 11 decimals. I did that just to match with the given answer.

from numpy import array, mean, var, std

arr = []
n, m = map(int, input().split())

for _ in range(n):
    arr.append([*map(int, input().split())])
arr = array(arr)

print(mean(arr, axis=1))
print(var(arr, axis=0))
print(round(std(arr), 11))

2 months ago+ 1 comment

I did two things to make it work for all the test cases:

1) commented out printoptions that were recommended in the previous examples, but were not needed in this question

2) added rounding to 11th decimal place to calculate std: print(numpy.round(numpy.std(arr, axis = None),11))

Hope thois helps

2 months ago+ 0 comments

Thanks Edvard

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449 Discussions

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For Python3 Platform

It isn't mentioned to round off the standard deviation to 11 decimals. I did that just to match with the given answer.

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