def solve(n, r):
    fact = 1
    for i in range(max(r, n-r)+1, n+1):
        fact*=i
    return (fact//math.factorial(min(r, n-r)))%142857

import functools
import sys

class MathEngine():
    """A collection of algorithms for Modular Arithmetics.

       References:
           [1] Granville, A. "Binomial coefficients modulo prime powers".
           [2] Knuth, D. "The Art of Computer Programming", vol 1.
           [3] https://en.wikipedia.org/wiki/Extended_Euclidean_algorithm#Polynomial_extended_Euclidean_algorithm
    """
    def __init__(self):
        self.pe = None
        self._cache_factorial = {}

    def binomial(self, n, m):
        """Find the binomial (n m) = n!/m!/(n-m)!."""
        if m == 0:
            if n == 0:
                return 0
            else:
                return 1
        b = self.factor_binomial(n, m)
        result = self.factors_to_integer(b)
        return result

    def binomial_prime_power(self, n, m, p):
        """Find the max power of `p` which divides a binomial (n m)."""
        result = self._number_of_carries(n-m,m,p)
        return result

    def factor_binomial(self, n, m):
        """Factor the binomial (n m) into primes.

        The algorithm is based on Kummer's theorem [1, page 7].
    
        Result:
            {d1:p1, ..., dn:pn}, so that (n m) = d1^p1 * ... * dn^pn.
        """
        result = {}
        for p in self.primes(n+1):
            power = self.binomial_prime_power(n,m,p)
            if power > 0:
                result[p] = power
        return result

    def factor_integer(self, n):
        """Factor n into primes.
    
        Result:
            {d1:p1, ..., dn:pn}, so that n = d1^p1 * ... * dn^pn.
        """
        result = {}
        for p in self.primes(n+1):
            power = 0
            while n % p == 0 and n != 1:
                n = n // p
                power += 1
            if power > 0:
                result[p] = power
            if n == 1:
                break
        return result

    def factor_factorial(self, n):
        """Factor the factorial of n into primes.

        The algorithm is based on the Kummer's theorem formulated for binomial coefficients;
        for the case of factorials see [1, eq.(17)] or [2, eq.(1.2.5.8)].
    
        Result:
            {d1:p1, ..., dn:pn} such that n! = d1^p1 * ... * dn^pn.
        """
        result = {}
        for prime in self.primes(n+1):
            k = n
            result[prime] = 0
            while k > 0:
                k = k // prime
                result[prime] += k
        return result

    def factorial(self, n, p=0, mod=0):
        """Find the product of all integers <= n, i.e. the factorial of n;
        if p > 0 exclude integers divisible by p; if mod > 0 find result
        modulo mod."""
        _cache_key = (n,p,mod)
        if _cache_key in self._cache_factorial:
            return self._cache_factorial[_cache_key]
        result = 1
        if p == 0:
            if mod == 0:
                for k in range(1,n+1):
                    result *= k
            else:
                for k in range(1,n+1):
                    result = (result*k) % mod
        else:
            if mod == 0:
                for k in range(1,n+1):
                    if k % p != 0:
                        result *= k
            else:
                for k in range(1,n+1):
                    if k % p != 0:
                        result = (result*k) % mod
        self._cache_factorial[_cache_key] = result
        return result 

    def factors_to_integer(self, n):
        result = 1
        for prime,power in n.items():
            result *= prime**power
        return result

    def gcd_extended(self, a, b):
        """Find gcd(a,b) and coefficients s,t of the Bezout's identity, such that
        `a*s + b*t = gcd(a,b)`. See [3] for more details.

        Result:
            (gcd(a,b), s, t)
        """
        s, s_old = 0, 1
        t, t_old = 1, 0
        r, r_old = b, a
        while r != 0:
            k = r_old // r
            r_old, r = r, r_old - k * r
            s_old, s = s, s_old - k * s
            t_old, t = t, t_old - k * t
        return r_old, s_old, t_old

    def integer_digits(self, n, p):
        """Find digits of n in the p representation.

        Result:
            [a0,...,ak], such that n = a0 + a1*p + ... + ak*p^k, where ai < p.
        """
        result = []
        while n > 0:
            result.append(n % p)
            n //= p
        return result

    def integer_digits_len(self, n, p):
        result = 1
        while n > 0:
            result += 1
            n //= p
        return result

    def mod_binomial(self, n, m, mod):
        """Find the reminder from the division of the binomial (n m) by mod.

        The algorithm is simple and slow, but less prone to errors comparing
        to the faster and more complex generalized Lucas algorithm, for more
        details see `mod_binomial_lucas` method.
        """
        binomial_factors = self.factor_binomial(n, m)
        result = 1
        for prime, exp in binomial_factors.items():
            result = (result * pow(prime, exp, mod)) % mod
        return result

    def mod_binomial_lucas(self, n, m, p, q=1):
        """Find the reminder form the division of the binomial (n m) by p^q,
        where mod is a prime number. This routine employs Lucas' Theorem (for q=1)
        and its generalization for (q>1), see [1, Theorem 1].
        """
        e0 = self.binomial_prime_power(n,m,p)
        qq = q-e0
        if qq < 0:
            return 0
        p_e0, p_q, p_qq = p**e0, p**q, p**qq
        r = n - m
        d = self.integer_digits_len(n, p)
        _ni, _mi, _ri = n, m, r
        _least_positive_residue_n = []
        _least_positive_residue_m = []
        _least_positive_residue_r = []
        for i in range(0, d):
            _least_positive_residue_n.append(_ni % p_qq)
            _least_positive_residue_m.append(_mi % p_qq)
            _least_positive_residue_r.append(_ri % p_qq)
            _ni //= p
            _mi //= p
            _ri //= p
        _factorial = [1]
        curr = 1
        for x in range(1,p_qq):
            if x % p != 0:
                curr = (curr*x) % p_qq
            _factorial.append(curr)
        result, i = 1, 0
        aaa, bbb, ccc = 1, 1, 1
        for i in range(0, d):
            aa = _least_positive_residue_n[i]
            bb = _least_positive_residue_m[i]
            cc = _least_positive_residue_r[i]
            a = _factorial[aa]
            b = _factorial[bb]
            c = _factorial[cc]
            aaa = (aaa*a) % p_qq
            bbb = (bbb*b) % p_qq
            ccc = (ccc*c) % p_qq
            i += 1
        result = aaa * self.mod_inverse(bbb*ccc % p_qq, p_qq) % p_qq
        if p != 2 or qq < 3:
            result *= (-1)**self._number_of_carries(m,r,p,qq-1)
        result = (result * p_e0) % p_q
        return result

    def _least_positive_residue(self, n, j, p, q):
        """Helper for mod_binomial_lucas method"""
        result = (n//p**j) % p**q
        return result

    def _number_of_carries(self, m, r, p, j=0):
        """Helper for mod_binomial_lucas method"""
        result, carry, jj = 0, 0, 0
        while (m > 0 or r > 0):
            if (m % p) + (r % p) + carry >= p:
                carry = 1
            else:
                carry = 0
            if jj >= j:
                result += carry
            m, r = m // p, r // p
            jj += 1
        return result

    def mod_chinese(self, rs):
        n = functools.reduce(lambda a,b: a*b, rs.keys(), 1)
        result = 0
        for ni,ai in rs.items():
            nn = n // ni
            _, ri, si = self.gcd_extended(ni, nn)
            ei = si*nn
            result += ai*ei
        result = result % n
        return result

    def mod_inverse(self, n, mod):
        r, s, t = self.gcd_extended(n, mod)
        if r != 1:
            return None
        return s

    def primes(self, n):
        return self.pe.primes(n)

class Solver(object):
    def __init__(self):
        self.me = MathEngine()
        self.mod = 142857

    def solution(self, n, r):
        """Find solution to the "nCr" problem."""
        mod_factors = {3: 3, 11: 1, 13: 1, 37: 1}
        mods = {p**q:self.me.mod_binomial_lucas(n, r, p, q) for p,q in mod_factors.items()}
        result = self.me.mod_chinese(mods)
        return result

if __name__ == '__main__':
    T = int(sys.stdin.readline())
    solver = Solver()
    for i in range(T):
        n, r = [int(num) for num in sys.stdin.readline().split()]
        print(solver.solution(n, r))