fixed: words = {}

if name == 'main': s = input()

# Count character frequencies
for char in s:
    if char not in words:
        words[char] = 1
    else:
        words[char] += 1

fixed = sorted(words.items(), key=lambda item: (-item[1], item[0]))


for i, (char, freq) in enumerate(fixed):
    if i >= 3:  # Stop after printing the top 3
        break
    print(f"{char} {freq}")

I have just started learning and I was not aware of Counter Class and the method most_common()

Glad I came accross Boki's solution from 9 years back! Classes are a bit tough to understand though so I made something of my own.

from collections import Counter


if __name__ == '__main__':
    
    # sorting alphabetically so they occur in alphabetic order
    company_name = sorted(input())
    
    # count 3 most common characters
    three_most_common_chars = Counter(company_name).most_common(3)
    
    for char, freq in three_most_common_chars:
        print(f"{char} {freq}")
    
    for char, freq in three_most_common_chars:
        print(f"{char} {freq}")

Does anyone know why i keep getting this wrong:

import math import os import random import re import sys

words = {}

if name == 'main': s = input()

for x in range(len(s) - 1, -1, -1):
    if s[x] not in words:
        words[s[x]] = 1
    else:
        words[s[x]] += 1

# Sort the dictionary by frequency (ascending)
fixed = sorted(words.items(), key=lambda item: item[1])

# Display the sorted results
for char, freq in fixed:
    print(f"{char} {freq}")

As a one-liner (with one import: from collections import Counter):

print('\n'.join(f'{k} {v}' for k, v in Counter(sorted(input())).most_common(3)))