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  • jpconcerman
     + 0 comments
    from collections import Counter


if __name__ == '__main__':
s = input().strip()
ctr = Counter(s)
for key, item in sorted(ctr.items(), key=lambda x: (-x[1], x[0]))[:3]:
    print(f"{key} {item}")

  • apavaloaiestefa1
     + 0 comments

    solution using Counter:

    #!/bin/python3

import math
import os
import random
import re
import sys

from collections import Counter

if __name__ == '__main__':
    s = input()   
    my_c = Counter(s)
    
    sorted_desc_c = dict(sorted(my_c.items(), key = lambda x: (-x[1], x[0])))
    k = 0
    for letter, count in sorted_desc_c.items():
        if(k<3):
            print(letter, count)
            k += 1

  • hzerryn
     + 0 comments
    if __name__ == '__main__':
    s = input()
    
    counts = {}
    
    for i in s:
        counts[i] = s.count(i)
        
    counts = sorted(counts.items(), key=lambda x: (-x[1], x[0]))
    
    for i in range(3):
        print(counts[i][0], counts[i][1])

  • piras_2019843
     + 0 comments
    import math
import os
import random
import re
import sys
from collections import Counter


if __name__ == '__main__':
    s = input()

count= Counter(s)
sorted_items = sorted(count.items(), key=lambda x: (-x[1], x[0]))
for char, freq in sorted_items[:3]:
    print(char, freq)
    

    ``

  • shaswathkumar
     + 0 comments

    Did a little digging and found the Counter.most_common(n) method, which returns the list you need to iterate print(*) through. Sorted the string beforehand because .most_common(n) will sort by order of elements encountered.

    from collections import Counter


if __name__ == '__main__':
    s = sorted(input())
    s_count = Counter(s)
    [print(*entry) for entry in s_count.most_common(3)]