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1259 Discussions

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  • bizajva
     + 0 comments

    Is better solution using Counter (as i learnt from other posting), anyway here is my solution.

    from itertools import groupby

    if name == 'main':

    s = sorted(list(input()))

cap= [(k, len(list(g))) for k, g in groupby(s) ]

print (cap)
res = sorted(cap, reverse=True, key=lambda qty: qty[1])

    for x in range(3):
    print(res[x][0],res[x][1] )

  • kumarmayashanka1
     + 0 comments
    #!/bin/python3

import math
import os
import random
import re
import sys
from collections import Counter

if __name__ == '__main__':
    s = input()  # Get the input string
    
    # Count the frequency of each character
    counter = Counter(s)
    
    # Sort by frequency in descending order and by character in ascending order
    most_common = sorted(counter.items(), key=lambda x: (-x[1], x[0]))
    
    # Print the top 3 most common characters
    for i in range(3):
        char, count = most_common[i]
        print(char, count)

  • shreyescodes
     + 0 comments

    All TestCases Passed

    from collections import Counter

if __name__ == '__main__':
    s = input().strip()
    # Count the occurrences of each character
    count = Counter(s)
    # Sort by frequency (descending) and then alphabetically for ties
    sorted_count = sorted(count.items(), key=lambda x: (-x[1], x[0]))
    # Print the top three characters
    for char, freq in sorted_count[:3]:
        print(char, freq)

  • MisterBemo
     + 0 comments

    fixed: words = {}

    if name == 'main': s = input()

    # Count character frequencies
for char in s:
    if char not in words:
        words[char] = 1
    else:
        words[char] += 1

fixed = sorted(words.items(), key=lambda item: (-item[1], item[0]))


for i, (char, freq) in enumerate(fixed):
    if i >= 3:  # Stop after printing the top 3
        break
    print(f"{char} {freq}")

  • sanket_n_dube
     + 0 comments

    I have just started learning and I was not aware of Counter Class and the method most_common()

    Glad I came accross Boki's solution from 9 years back! Classes are a bit tough to understand though so I made something of my own.

    from collections import Counter


if __name__ == '__main__':
    
    # sorting alphabetically so they occur in alphabetic order
    company_name = sorted(input())
    
    # count 3 most common characters
    three_most_common_chars = Counter(company_name).most_common(3)
    
    for char, freq in three_most_common_chars:
        print(f"{char} {freq}")
    
    for char, freq in three_most_common_chars:
        print(f"{char} {freq}")