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  1. Prepare
  2. Python
  3. Strings
  4. Merge the Tools!
  5. Discussions

Merge the Tools!

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2609 Discussions

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  • komalatha_adapa1
     + 0 comments

    def merge_the_tools(string, k): li=[] for i in range(0,len(string),k): temp="" for j in range(k): temp=temp+string[i+j] li.append(temp) dup=[] for i in li: temp="" for j in i: if j not in temp: temp=temp+j dup.append(temp) for i in dup: print(i)

  • danemmanuel441
     + 0 comments

    def merge_the_tools(string, k): text = "" for i in string: text += i if len(text) == k: s = "".join(sorted(set(text), key=text.index)) print(s) text = ""

  • a00279833
     + 0 comments
    def merge_the_tools(string, k):
    text = ""
    for i in string:
        text += "".join(i)
        if len(text) == k:
            for i in range(len(text)):
                s = "".join(sorted(set(text), key=text.index))
            print(s)
            text = ""

  • subhashhkhandel1
     + 0 comments

    def merge_the_tools(string, k): # Iterate through the string in chunks of size k for i in range(0, len(string), k): # Extract the substring of length k s = string[i:i + k] # Remove duplicate characters while preserving order res = ''.join(dict.fromkeys(s)) print(res)

    if name == 'main': string, k = input(), int(input()) merge_the_tools(string, k)

  • 53_israel
     + 0 comments
    def merge_the_tools(string, k):
    
    n = len(string) // k
    aux = 0
    var = ''
    
    for i in range(len(string)):
        
        if aux == k:
            aux = 0
            var = set(list(var))
            print(''.join(var))
            var = ''
        aux += 1
        var += string[i]
    if aux == k:
        var = set(list(var))
        print(''.join(var))