def check1(e):
    return e[3]
def check2(p,d,flag,count):
    for i in p:
        if d==i[3]:
            count+=1
    if count==1:
        return True
    elif count>1:
        return False
p=[]
n=int(input())
data=input().split(" ")
data=[int(i) for i in data]
for i in range(n-2):
    j,k=i+1,i+2
    if data[i]+data[j]>data[k] and data[i]+data[k]>data[j] and data[j]+data[k]>data[i]:
        p.append([data[i],data[j],data[k],data[i]+data[j]+data[k]])
if len(p)<=1:
    if len(p)==0:
        print(-1)
    else:
        print(f'{p[0][0]} {p[0][1]} {p[0][2]}')
else:
    p.sort(reverse=True,key=check1)
    flag=check2(p,p[0][3],True,0)
    if flag==True:
        print(f'{p[0][0]} {p[0][1]} {p[0][2]}')
    else:
        count=0
        flag=check2(p,p[-1][3],True,0)
        if flag==True or flag==False:
            print(f'{p[-1][0]} {p[-1][1]} {p[-1][2]}')