Great breakdown of the system design process! Clarifying requirements upfront, addressing non-functional needs, and planning for scalability are crucial. The focus on trade-offs and component deep dives ensures a balanced and effective design.Read More

In that's not my neighbor, you find yourself drawn into a suspenseful story where your neighbor’s house holds horrifying secrets

Swift solution :

func maximumDraws(n: Int) -> Int {
    return n+1
}

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Problem Breakdown: If there is only 1 color of socks, the person just needs to remove 2 socks to guarantee a matching pair (since all socks are of the same color). If there are 2 colors of socks, the person could theoretically remove one of each color first, meaning that they need to remove 3 socks to ensure that they have a matching pair. For n colors, the worst-case scenario is that the person picks one sock from each color without getting a pair. In this case, after removing n socks, all would be of different colors. Therefore, to guarantee a matching pair, the person needs to remove n + 1 socks. Approach: The general formula is:

minimum socks to remove

𝑛 + 1 minimum socks to remove=n+1 Where n is the number of different colors of socks. def maximumDraws(n): return n + 1

Input handling

t = int(input()) # number of test cases for _ in range(t): n = int(input()) print(maximumDraws(n)) input 2 1 2 output 2 3

Function Definition: We need to create a function called maximumDraws that takes the number of colors of socks n as input and returns the minimum number of socks to remove to guarantee a matching pair.