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Maximum Draws
Maximum Draws
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In that's not my neighbor, you find yourself drawn into a suspenseful story where your neighbor’s house holds horrifying secrets
Swift solution :
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Problem Breakdown: If there is only 1 color of socks, the person just needs to remove 2 socks to guarantee a matching pair (since all socks are of the same color). If there are 2 colors of socks, the person could theoretically remove one of each color first, meaning that they need to remove 3 socks to ensure that they have a matching pair. For n colors, the worst-case scenario is that the person picks one sock from each color without getting a pair. In this case, after removing n socks, all would be of different colors. Therefore, to guarantee a matching pair, the person needs to remove n + 1 socks. Approach: The general formula is:
minimum socks to remove
𝑛 + 1 minimum socks to remove=n+1 Where n is the number of different colors of socks. def maximumDraws(n): return n + 1
Input handling
t = int(input()) # number of test cases for _ in range(t): n = int(input()) print(maximumDraws(n)) input 2 1 2 output 2 3
Function Definition: We need to create a function called maximumDraws that takes the number of colors of socks n as input and returns the minimum number of socks to remove to guarantee a matching pair.
int maximumDraws(int n) { if (n == 1 || n == 0) return 2; else return n + 1;
}
Heres my silly billy answer in C