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  1. Prepare
  2. Regex
  3. Repetitions
  4. Matching Zero Or More Repetitions
  5. Discussions

Matching Zero Or More Repetitions

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72 Discussions

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  • nsaivenkatesh
     + 0 comments
    Regex_Pattern = r'^\d{2,}[a-z]*[A-Z]*$'	# Do not delete 'r'.

  • nsaivenkatesh
     + 0 comments
    Regex_Pattern = r'^\d{2,}[a-z]{0,}[A-Z]{0,}$'	# Do not delete 'r'.

  • preethiannjacob
     + 0 comments

    Java 15

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Pattern pattern = Pattern.compile("^\\d{2,}[a-z]*[A-Z]*$");
        Matcher matcher = pattern.matcher(scanner.nextLine());
        boolean found = matcher.find();
        System.out.println(found);
    }
}

  • Solumna
     + 3 comments

    Following the logic given to us so far, This was my answer in java syntax

    ^[\\d\\d]\\d*[a-z]*[A-Z]*

    • my answer starts with 2 digits, followed by 0 or more digits
      • here 2,3+ digits should be okay

    Is there something wrong with my answer?

  • KrithikaEndrala
     + 0 comments
    Regex_Pattern = r'^\d{2,}[a-z]{0,}[A-Z]{0,}$'	# Do not delete 'r'.

import re

print(str(bool(re.search(Regex_Pattern, input()))).lower())