We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Regex
  3. Repetitions
  4. Matching {x} Repetitions
  5. Discussions

Matching {x} Repetitions

Sort by

recency

|

99 Discussions

|

  • lixoten
     + 0 comments

    What made this confusing, was that in a previous problem it stated that 0/zero did not count as even. But on this problem 0/zero is counted as even

  • preethiannjacob
     + 0 comments

    Java 15

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Pattern pattern = Pattern.compile("^[a-zA-Z02468]{40}[13579\\s]{5}$");
        Matcher matcher = pattern.matcher(scanner.nextLine());
        boolean found = matcher.find();
        System.out.println(found);
    }
}

  • jaybee7
     + 0 comments

    JavaScript

    var Regex_Pattern = /^[a-zA-Z02468]{40}[13579\s]{5}$/;

  • ontarian123456
     + 0 comments

    Note: zero counts as an even number.

  • KrithikaEndrala
     + 0 comments
    Regex_Pattern = r'^[a-zA-Z02468]{40}[\s13579]{5}$'	# Do not delete 'r'.

import re

print(str(bool(re.search(Regex_Pattern, input()))).lower())