Matching Same Text Again & Again

Sort by

recency

|

67 Discussions

|

  • + 0 comments

    Amazing tried this on.

  • + 0 comments
    Regex_Pattern = r'([a-z])(\w+)(\s)(\W+)(\d)(\D)([A-Z])([a-zA-Z])([aeiouAEIOU])(\S)\1\2\3\4\5\6\7\8\9\10'
    
  • + 0 comments

    Java 15:

    import java.io.*;
    import java.util.*;
    import java.util.regex.Pattern;
    import java.util.regex.Matcher;
    public class Solution {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            Pattern pattern = Pattern.compile("^([a-z])(\\w)(\\s)(\\W)(\\d)(\\D)([A-Z])([a-zA-Z])([aeiouAEIOU])([\\S])\\1\\2\\3\\4\\5\\6\\7\\8\\9\\10$");
            Matcher matcher = pattern.matcher(scanner.nextLine());
            System.out.println(matcher.find());
        }
    }
    
  • + 0 comments
    Regex_Pattern = r'^([a-z]\w\s\W\d\D[A-Z][A-Za-z][aeiouAEIOU]\S)\1$'    # Do not delete 'r'.
    import re
    
    print(str(bool(re.search(Regex_Pattern, input()))).lower())
    
  • + 0 comments

    java

    public static void main(String[] args) {        
            Regex_Test tester = new Regex_Test();
            tester.checker("^([a-z])(\\w)(\\s)(\\W)(\\d)(\\D)([A-Z])([A-z])([aeiouAEIOU])(\\S)\\1\\2\\3\\4\\5\\6\\7\\8\\9\\10$"); // Use \\ instead of using \     
        }