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  1. Prepare
  2. Regex
  3. Introduction
  4. Matching Digits & Non-Digit Characters
  5. Discussions

Matching Digits & Non-Digit Characters

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164 Discussions

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  • Sokeen
     + 0 comments

    82lotteryhack

  • preethiannjacob
     + 0 comments

    Java 15

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        // Pattern pattern = Pattern.compile("\\d\\d\\D\\d\\d\\D\\d\\d\\d\\d");     \\WORKS
        Pattern pattern = Pattern.compile("(\\d{2}\\D){2}\\d{4}");
        Matcher matcher = pattern.matcher(scanner.next());
        boolean found = matcher.find();
        System.out.println(found);
    }
}

  • yassinec2022
     + 0 comments

    my python solution: r"^(\d{2}\D){2}\d{4}"

  • gerlee_gerlee71
     + 0 comments

    java pattern : "^([0-9]{2}\D{1}){2}[0-9]{4}" or (\d{2}\D){2}\d{4}

  • estevaopbsantos
     + 0 comments

    java solution

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Pattern pattern = Pattern.compile("(\\d{2}\\D){2}\\d{4}");
        Matcher matcher = pattern.matcher(scanner.next());
        System.out.println(matcher.find());
    }
}