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  1. Prepare
  2. Algorithms
  3. Strings
  4. Mars Exploration
  5. Discussions

Mars Exploration

  • patrickgao2020
     + 0 comments

    Here is my one line Python solution!

    def marsExploration(s):
    return len([True for letter in range(len(s)) if s[letter] != ["S", "O", "S"][letter % 3]])