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  2. Python
  3. Python Functionals
  4. Map and Lambda Function
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Map and Lambda Function

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480 Discussions

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  • imam_alfaridzi
     + 0 comments

    Here's my code:

    cube = lambda x: x**3

def fibonacci(n):
    res = [0, 1]
    for i in range(2, n):
        res.append(res[i - 1] + res[i - 2])
    return res[:n]

  • ghoshankit1729
     + 0 comments

    cube = lambda x:x**3

    def fibonacci(n): # return a list of fibonacci numbers f = [0] a, b = 0, 1

    if n == 0:
    return []
else:
    for i in range(1, n):
        a, b = b, a + b
        f.append(a)
return f

    if name == 'main': n = int(input()) print(list(map(cube, fibonacci(n))))

  • rejin_gunasekar1
     + 0 comments
    cube = lambda x: x**3
def fibonacci(n):
    f = []
    a, b = 0, 1
    for _ in range(n):
        f.append(a)
        a, b = b, a + b
    return f
if __name__ == '__main__':
    n = int(input())
    print(list(map(cube, fibonacci(n))))

  • lautterm
     + 0 comments
    cube = lambda x: x**3

def fibonacci(n):
    fibonacci_numbers = []
    an = 0
    an_1 = 1
    
    for _ in range(n):
        if len(fibonacci_numbers) == 0:
            fibonacci_numbers.append(an)
        elif len(fibonacci_numbers) == 1:
            fibonacci_numbers.append(an_1)
        else:
            an_2 = an + an_1
            fibonacci_numbers.append(an_2)
            an = an_1
            an_1 = an_2
    
    return fibonacci_numbers[:n]

if __name__ == '__main__':
    n = int(input())
    print(list(map(cube, fibonacci(n))))

    I tried to write my code as comprehensible as possible!

  • druavhm
     + 0 comments
    cube = lambda x:x**3

def fibonacci(n):
    arr = []
    for i in range(n):
        if i == 0 or i == 1:
            arr.append(i)
        else:
            x = arr[i-1] + arr[i - 2]
            arr.append(x)
    return arr

if __name__ == '__main__':
    n = int(input())
    print(list(map(cube, fibonacci(n))))