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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Forming a Magic Square
  5. Discussions

Forming a Magic Square

  • jory2
     + 0 comments

    My Javascript Solution:

    function formingMagicSquare(s) {
    let possible_a_b = [
        [-3,-1],
        [-3,1],
        [-1,-3],
        [-1,3],
        [1,-3],
        [1,3],
        [3,-1],
        [3,1]
    ]
    let costs = [0,0,0,0,0,0,0,0]
    for (let i = 0; i < possible_a_b.length; i++) {
        let [a,b] = possible_a_b[i];
        let magicSquare = [
            [5-b, 5+(a+b), 5 -a],
            [5-(a-b), 5, 5+(a-b)],
            [5+a, 5-(a+b), 5+b]
        ]
        for (let j = 0; j < s.length; j++) {
            for (let k = 0; k < s[j].length; k++) {
                if (s[j][k] !== magicSquare[j][k]) {
                    costs[i] = costs[i] + Math.abs(s[j][k] - magicSquare[j][k])
                }
            }
        }
    }
    costs.sort((a,b) => a -b)
    return costs[0]

    }