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  1. Prepare
  2. Linux Shell
  3. Arrays in Bash
  4. Lonely Integer - Bash!
  5. Discussions

Lonely Integer - Bash!

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190 Discussions

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  • wilsonnianopop
     + 0 comments

    My solution: !/bin/bash

    contador=0 auxiliar=""

    read entrance

    read -a entrance2

    for(( i=0; i<"You can't use 'macro parameter character #' in math mode{#entrance2[@]}"; l++ )); do if(("{entrance2[l]}"));then contador=$((contador+1)) fi

    done

if(("$contador" == "1")); then
    auxiliar="${entrance2[i]}"
    break
fi

    done

    echo "$auxiliar"

  • ataua_doederlein
     + 1 comment
    awk '  
BEGIN { res = 0 }  

NR == 2 {  
    for (i = 1; i <= NF; i++) {  
    el = $i  
    if (el in arr) {  
          res -= el  
      } else {  
          arr[el] = el  
          res += el  
      }  				
  }  		
  print res  
}'

  • nguyendang1547
     + 0 comments

    read n read -a array

    tmp=0 for value in "((tmp^value)) done echo $tmp

  • superidmaker
     + 0 comments
    read N

# Read the space-separated integers into an array and find the unique integers with their counts

echo "$(< /dev/stdin)" | tr ' ' '\n' | sort | uniq -u

  • cc111091
     + 1 comment
    read n
read -a arr

temp=${arr[0]}
for n in ${arr[@]:1}; do temp=$(( temp ^ n )); done

echo $temp