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  1. Prepare
  2. Python
  3. Basic Data Types
  4. List Comprehensions
  5. Discussions

List Comprehensions

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1728 Discussions

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  • SVVBathini
     + 0 comments

    For Python3

    x = int(input())
y = int(input())
z = int(input())
n = int(input())

print([[i, j, k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if i+j+k != n])

  • devgomes1223
     + 1 comment

    I had success with this code: 

     new_list = []

for i in range(x + 1):
    for j in range(y + 1):
        for k in range(z + 1):
            if (i + j + k != n):
                new_list.append([i, j, k])

print(new_list)

  • kumar_karanq98
     + 0 comments

    if name == 'main': x = int(input()) y = int(input()) z = int(input()) n = int(input())

      ls = [[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if i+j+k!=n ]
  print(ls)

  • claudelounou75
     + 0 comments

    My python Code

    if __name__ == '__main__':
    x = int(input())
    y = int(input())
    z = int(input())
    n = int(input())
    
    liste = []
    for i in range(0,x+1):
        for j in range(0,y+1):
            for k in range(0,z+1):
                if (i + j + k) != n:
                    liste.append([i,j,k])
                    
    print(liste)

  • ma3443672
     + 0 comments

    List comprehension is a nested loop . we can create this in two ways

    the first way

    a = int(input()) b = int(input()) c = int(input()) n = int(input()) listt = [] for i in range(a+1): for j in range(b+1): for k in range(c+1): if i+j+k != n: listt.append([i,j,k])
    print(listt)

    the second way

    a = int(input()) b = int(input()) c = int(input()) n = int(input()) listt = [[i,j,k] for i in range(a+1)for j in range(b+1)for k in range(c+1)if (i+j+k) !=n]
    print(listt)