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  3. Linear Algebra Foundations
  4. Linear Algebra Foundations #1 - Matrix Addition
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Linear Algebra Foundations #1 - Matrix Addition

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  • h2500032039
     + 0 comments

    include

    int main() { int A[3][3] = { {1, 2, 3}, {2, 3, 4}, {1, 1, 1} };

    int B[3][3] = {
    {4, 5, 6},
    {7, 8, 9},
    {4, 5, 7}
};

int C[3][3]; // Resultant matrix

// Perform matrix addition: C = A + B
for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
        C[i][j] = A[i][j] + B[i][j];
    }
}

// Print the resulting matrix
printf("Resultant matrix (C = A + B):\n");
for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
        printf("%d ", C[i][j]);
    }
    printf("\n");
}

return 0;

    }

  • kl2500031290
     + 0 comments

    Matrix Addition

    Add the two matrices given below and find the integers corresponding to , , , , , , , , and :

    [1 2 3] [4 5 6] [a b c] [2 3 4] + [7 8 9] = [d e f] [1 1 1] [4 5 7] [g h i] To submit your answer, enter the resultant values of each of the nine integers (i.e., , , , , , , , , and ) on a new line and click Submit Code.

    Input Format

    There is no input for this challenge; calculate the values of through using the matrices given above.

    Output Format

    In the text box below, enter the values of each of the nine integers on a new line. You must have a total of nine lines of output and the integers must be printed in order (i.e., , , , , , , , , and , respectively).

    Sample Output

    1 2 3 4 5 6 7 8 9

  • netanya_martin
     + 0 comments

    As a few other people commented, the parser used to collect the answers on this question sucks.

    # n_rows=3 #int(input()) # first get number of rows in maxtrix
# n_mats=2 #int(input()) # then get number of matrices

# m_names = ['mtrx_'+str(j) for j in range(0,n_mats)]

# for i in range(0,n_mats):
#     m=[]
#     for r in range(0,n_rows):
#         row = [int(x) for x in input().split()]
#         m.append(row)
#     m_names[i] = m

# # add 2 nxn matrices:
# def add_matrices(m1,m2):
#     return[[m1[j][k]+m2[j][k] for k in range(len(m1))] for j in range(len(m1))]
# my_matrix = add_matrices(m_names[0], m_names[1])

# # print output
# for j in range(len(my_matrix)):
#     for k in range(len(my_matrix)):
#         print(my_matrix[j][k])

my_matrix = [[5,7,9],[9,11,13],[5,6,8]]
# print output
for j in range(len(my_matrix)):
    for k in range(len(my_matrix)):
        print(my_matrix[j][k])

  • sashinidawpadi
     + 0 comments
    int[][] m1 = { {1, 2, 3}, {2,3,4} , {1,1,1} }; 
        int[][] m2 = { {4,5,6}, {7,8,9},{4,5,7} }; 
        int[][] sum = new int[3][3];
        for(int i=0;i<3;i++){
           for(int j=0;j<3;j++){
           sum[i][j] = m1[i][j] + m2[i][j];
           System.out.println(sum[i][j]);
        }
        }

  • chisom213
     + 0 comments
    if __name__ == '__main__':
  a1, a2, a3 = [1, 2, 3], [2, 3, 4], [1, 1, 1]
  b1, b2, b3 = [4, 5, 6], [7, 8, 9], [4, 5, 7]
  c1, c2, c3 = [], [], []
  for i in range(len(a1)):
    c1.append(a1[i] + b1[i])
    c2.append(a2[i] + b2[i])
    c3.append(a3[i] + b3[i])

  print(*c1, sep='\n')
  print(*c2, sep='\n')
  print(*c3, sep='\n')