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  • + 0 comments

    Here is my solution in java, javascript, python, C, C++, Csharp HackerRank Yet Another KMP Problem Solution

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    Adding another resource.

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    Here is the solution of Yet Another KMP Problem Click Here

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    Here is problem solution - https://programs.programmingoneonone.com/2021/07/hackerrank-yet-another-kmp-problem-solution.html

  • + 1 comment

    TypeScript solution (24/37 passes test cases)

    class Pivote {
      index: number;
      pivote: number;
      isPrimero: boolean;
      constructor() {
        this.index = -1;
        this.pivote = 0;
        this.isPrimero = false;
      }
    }
    
    const letters: string[] = [
      "a",
      "b",
      "c",
      "d",
      "e",
      "f",
      "g",
      "h",
      "i",
      "j",
      "k",
      "l",
      "m",
      "n",
      "o",
      "p",
      "q",
      "r",
      "s",
      "t",
      "u",
      "v",
      "w",
      "x",
      "y",
      "z"
    ];
    
    const isZero = (number: number) => number === 0;
    
    function kmp(xArray: number[]): string {
      // Write your code here
      const pivote = new Pivote();
      xArray.forEach((item: number, index: number) => {
        if (!isZero(item)) {
          if (pivote.pivote) {
            if (!(pivote.pivote < item)) {
              if (pivote.pivote !== item) {
                pivote.pivote = item;
                pivote.isPrimero = false;
                pivote.index = index;
              }
            }
          } else {
            pivote.index = index;
            pivote.isPrimero = index === 0 ? false : true;
            pivote.pivote = item;
          }
        }
      });
      let string: string = letters[pivote.index];
      if (pivote.isPrimero) {
        const segundoPiv: Pivote = new Pivote();
        for (let i = pivote.index + 1; i < xArray.length; i++) {
          if (!isZero(xArray[i])) {
            segundoPiv.index = i;
            segundoPiv.pivote = xArray[i];
            break;
          }
        }
        xArray.forEach((item: number, index: number) => {
          if (pivote.pivote === item && pivote.index === index) {
            for (let i = 0; i < segundoPiv.pivote; i++) {
              string += letters[segundoPiv.index];
            }
            for (let i = 0; i < pivote.pivote - 1; i++) {
              string += letters[pivote.index];
            }
          } else if (segundoPiv.pivote !== item || segundoPiv.index !== index) {
            for (let i = 0; i < item; i++) {
              string += letters[index];
            }
          }
        });
      } else {
        xArray.forEach((item: number, index: number) => {
          for (
            let i = 0;
            i <
            (pivote.pivote === item && pivote.index === index ? item - 1 : item);
            i++
          ) {
            string += letters[index];
          }
        });
      }
      return string;
    }