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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Number Line Jumps
  5. Discussions

Number Line Jumps

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3982 Discussions

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  • sharshitsingh007
     + 0 comments

    C++: Try to write it in mathematical expression form string kangaroo(int x1, int v1, int x2, int v2) { if(v1==v2){ return (x1==x2)? "YES":"NO"; } if((x2-x1)%(v1-v2)==0 && (x2-x1)/(v1-v2)>=0){ return "YES"; } return "NO";

    }

  • henrylong7191
     + 0 comments

    ` def kangaroo(x1, v1, x2, v2):

    if v1 == v2:
    return 'YES' if x2 == x1 else 'NO'

ans = (x2 - x1) / (v1 - v2)

return 'YES' if ans >= 0 and ans.is_integer() else 'NO'

  • billwu402
     + 0 comments
    def kangaroo(x1, v1, x2, v2):
    # Write your code here
    if (x1 - x2) * (v1 - v2) < 0:
        if abs(x1 - x2) % abs(v1 - v2) == 0:
            return "YES"
        else:
            return "NO"
    else:
        return "NO"

  • jamesbondyeboah
     + 0 comments
    function kangaroo(x1: number, v1: number, x2: number, v2: number): string {
    // Write your code here
    let position1:number = x1;
    let position2:number = x2;
    if (v2 < v1){
        for(let x=0; x<10000; x++){
            position1+=v1;
            position2+=v2;
            if(position1 === position2){
                return 'YES';
            } 
        }
    }
    return 'NO';
}

  • johnson_david_x
     + 0 comments

    This can be solved without itteration. Use deltaV (v2-v1) and deltaX (x1-x2) to catch the edge cases:

    1. deltaX and deltaV are both 0. Meet at every hop
    2. same velocity, different starts. Never meet.
    3. deltaV does not divide evenly by deltaX ... mod(deltaV, deltaX) != 0
    4. deltaX/deltaV is a negative number.