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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Jumping on the Clouds
  5. Discussions

Jumping on the Clouds

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3285 Discussions

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  • mirianquispe1505
     + 0 comments
    function jumpingOnClouds(c: number[]): number {
    let jumps = 0
    for(let i=0; i < c.length - 1; i++){
        const nextDoubleCloud = c[i + 2]
        if(nextDoubleCloud == 0) {
            i++
        }
        jumps++
    }
    return jumps
}

  • wifivop476
     + 0 comments

    Jumping on the Clouds sounds like such a fun and creative concept! Whether it's about tackling challenges or dreaming big, it's a reminder to aim high. Just like in life, though, it’s always smart to stay grounded while pursuing those big dreams. What’s the story behind this idea?

  • vishwasai160599
     + 0 comments

    def jumpingOnClouds(c): # Write your code here cnt=0 i=0 while i+2

  • afzal_saiyed931
     + 0 comments
    def jumpingOnClouds(c):
    # Write your code here
    
    jump_count = 0
    counter = 0
    n = len(c)
    while counter < (n - 1):
        if counter + 2 < n and c[counter + 2] == 0:
            counter += 2
        else:
            counter += 1
        jump_count += 1
    return jump_count

  • pavelbaitalik
     + 0 comments

    Solution i have tried::: Java 

    public static int jumpingOnClouds(List<Integer> c) {
// Write your code here
int jump=0,temp=0,k=0;

       for(int j=k;j<c.size();j++){

     if( c.get(j)==0){
        temp++;
     }
    if (c.get(j)==1)
    {
        k=j;
         jump+=temp/2;
        temp=0;
        jump++;


    }
       }

         if (c.get(c.size()-1)==0 && c.get(c.size()-2)==0) {
           jump++;
       }
    return jump;
}