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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Jumping on the Clouds: Revisited
  5. Discussions

Jumping on the Clouds: Revisited

  • pt023150
     + 0 comments
        java 8

    int e = 100;
    for (int i = 1; i <= c.length; i++) {
        int jump = (k * i) % c.length;

        if (jump == 0 && c[jump] == 1) {
            e = e - 3;
            break;
        }
        if (jump == 0) {
            e = e - 1;
            break;

        } else if (c[jump] == 1) {
            e = e - 3;

        } else {
            e = e - 1;
        }

    }
    return e;