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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 2: Conditional Statements: Switch
  5. Discussions

Day 2: Conditional Statements: Switch

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366 Discussions

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  • sazidthe1
     + 0 comments

    Here's my solution:

    function getLetter(s) {
    let firstChar = s.charAt(0);
    let letter;
    switch (true) {
        case new Set(['a','e','i','o','u']).has(firstChar):
            letter = "A";
            break;
        case new Set(['b','c','d','f','g']).has(firstChar):
            letter = "B";
            break;
        case new Set(['h','j','k','l','m']).has(firstChar):
            letter = "C";
            break;
        default:
            letter = "D";
   }
   return letter;
}

  • julianbacab_dc7
     + 0 comments

    This is my solution

    function getLetter(s) {
    let letter = s;
    
    
    // Write your code here
    switch(true) {
        case ["a","e","i","o","u"].includes(letter[0]) :
                letter = "A";
                break;
        case ["b","c","d","f","g"].includes(letter[0]):
                letter = "B";
                break;
        case ["h","j","k","l","m"].includes(letter[0]):
                letter = "C";
                break;
        case ["n","p","q","r","s", "t", "v", "w","x","y","z"].includes(letter[0]):
                letter = "D";
                break;
    }
    
    return letter;
}

  • praveen111890
     + 0 comments

    function getLetter(s) { let letter; // Write your code here let charAtFirst = s[0];

    const set1 = ['a','e','i','o','u'];
const set2 = ['b', 'c', 'd', 'f', 'g'];
const set3 = ['h','j','k', 'l', 'm'];
const set4 = ['n','p','q','r','s','t','v','w','x','y','z'];

switch(true) 
{
    case set1.indexOf(charAtFirst) !== -1:
        letter = 'A';
        break;
    case set2.indexOf(charAtFirst) !== -1:
        letter = 'B';
        break;
    case set3.indexOf(charAtFirst) !== -1:
        letter = 'C';
        break;
    case set4.indexOf(charAtFirst) !== -1:
        letter = 'D';
        break;    
    default:
        letter = set1.indexOf(charAtFirst);    
}

return letter;

    }

  • ayanrazvi08
     + 0 comments

    function getLetter(s) { let letter; let a = ["a","e","i","o","u"]; let b = ["b","c", "d", "f","g"]; let c = ["h", "j", "k", "l", "m"];

    //     // Write your code here
// return a.includes(s[0])
//     if(a.includes(s[0])){

//    return "A"
//     }else{
//         return "no"

    // }
let firstChar = s[0]

    switch (true) { case a.find(item => item === firstChar) !== undefined: letter = "A"; break; case b.includes(firstChar): letter = "B"; break; case c.includes(firstChar): letter = "C"; break; default: letter = "D"; }

    return letter;

    }

    commented code is for understanding

  • karenbanci1
     + 0 comments
    function getLetter(s) {
  let letter;
  // Write your code here

  const i = 0;
  switch (true) {
    case new Set(["a", "e", "i", "o", "u"]).has(s.charAt(i)):
      letter = "A";
      break;
    case new Set(["b", "c", "d", "f", "g"]).has(s.charAt(i)):
      letter = "B";
      break;
    case new Set(["h", "j", "k", "l", "m"]).has(s.charAt(i)):
      letter = "C";
      break;
    default:
      letter = "D";
  }

  return letter;
}