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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 2: Loops
  5. Discussions

Day 2: Loops

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766 Discussions

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  • bouazizfarouk3
     + 0 comments

    THIS IS MINE:

    function vowelsAndConsonants(s) {
    const VOWLES = new Set(['a', 'e', 'i', 'o', 'u']);
    let sConsonants = '';
    
    for (let char of s) {
        VOWLES.has(char) ? console.log(char) : sConsonants += char + '\n';
    }

    console.log(sConsonants);
}

  • chocoaid
     + 0 comments

    To add to the multiple solutions posted, this was my method:

    function vowelsAndConsonants(s) {

    const vowelArray = ["a", "e", "i", "o", "u"];
let outputVowel = ""; 
let outputConsonant = ""; 

for (let i = 0, len = s.length; i < len; i++) {

    if (vowelArray.includes(s[i])) {
        outputVowel += s[i] + '\n';
    } else {
        outputConsonant += s[i] + '\n';

    }

}

console.log(outputVowel + outputConsonant)

    }

  • shubhamdhapola12
     + 0 comments
    function vowelsAndConsonants(s) {
    let vowelsArray = ['a','e','i','o','u'];
    let vowels = []
    let consonants = []

    for(let char of s) {
        vowelsArray.includes(char) ? vowels.push(char) : consonants.push(char)
    }

    let vowels_and_consonant = [...vowels, ...consonants]
    vowels_and_consonant.forEach(elem => console.log(elem))

}

  • chris_guthrie92
     + 0 comments

    Newby, doing things very slowly, but thouroughly. Method goes throught the string twice, Once for vowels, and second time for consonants.

    function vowelsAndConsonants(s) { for (let x = 0; x < s.length; x++){ if(s[x]=='a' || s[x]=='e' || s[x]=='i' || s[x]=='o' || s[x]=='u'){ console.log(s[x]) } } for (let x = 0; x < s.length; x++){ if (s[x]!='a' && s[x]!='e' && s[x]!='i' && s[x]!='o' && s[x]!='u'){ console.log(s[x]) } } }

  • singhkunj007
     + 0 comments
    function vowelsAndConsonants(s) {
    for (let i = 0; i < s.length; i++) {
        if (s[i] == "a" || s[i] == "e" || s[i] == "i" || s[i] == "o" || s[i] == "u"){
            console.log(s[i])
        }
    }
    
     for (let i = 0; i < s.length; i++) {
        if (s[i] !== "a" && s[i] !== "e" && s[i] !== "i" && s[i] !== "o" && s[i] !== "u"){
            console.log(s[i])
        }
    }
}