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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 5: Arrow Functions
  5. Discussions

Day 5: Arrow Functions

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442 Discussions

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  • Bye_Shuvo
     + 0 comments
    const modifyArray = (nums) => {
    return nums.map((num)=>{return (num%2 === 0)?(num*2):(num*3)})
}

    this is the simpliest way to do it , where map() creates a new array from calling a function for every array element and does not change the original array. then just return the new array for modifyArray function.

  • jonlle19
     + 0 comments
    function modifyArray(nums) {
    return nums.map(num => num % 2 === 0 ? num * 2 : num * 3)
}

  • alerpiniere
     + 0 comments
    function modifyArray(nums) {
    return nums.map(n => {
        return n * (2 + n%2)
    })
}

  • uisamratc
     + 0 comments

    In JS

    function modifyArray(nums) {
    const res = nums.map((val) => {
  if (val % 2 == 0) {
    return val * 2;
  } else {
    return val * 3;
  }
});

return res;

}

  • ash_rabbi
     + 0 comments

    Managed to fit in one line:

    function modifyArray(nums) {
    return nums.map(n => n % 2 ? n * 3 : n * 2);
}