That’s a great challenge to practice string manipulation in Java! The Prepare Java Strings – Java String Reverse problem on HackerRank is simple yet effective for building a strong foundation! Dental clinic near me

            String A = sc.next();
    String revA = new String();

    for(int i=A.length(); i>0; i--){
        //revA += A.substring(i-1,i);
        revA = revA.concat(A.substring(i-1,i));
    }

    if(A.compareToIgnoreCase(revA) == 0){
        System.out.print("Yes");
    } else {
        System.out.print("No");
    }

Scanner sc=new Scanner(System.in); String A=sc.next(); /* Enter your code here. Print output to STDOUT. */ int len =A.length(); String rev="";

        for(int i=len-1;i>=0;i--){
            rev+=A.charAt(i);
        }

     if(rev.equals(A)){
        System.out.println("Yes");
    }else{
        System.out.println("No");
    }
 sc.close(); 

import java.io.; import java.util.;

public class Solution { public static void main(String[] args) { Scanner sc=new Scanner(System.in); String A=sc.next();
String revA = new StringBuilder(A).reverse().toString(); if (A.equals(revA)) { System.out.println("Yes"); } else { System.out.println("No"); } } }

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);
String A=sc.next();
/* Enter your code here. Print output to STDOUT. */        
String revA = new StringBuilder(A).reverse().toString();

if (A.equals(revA)) {
    System.out.println("Yes");
} else {
    System.out.println("No");
}

}