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  1. Prepare
  2. Java
  3. Strings
  4. Java Regex
  5. Discussions

Java Regex

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647 Discussions

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  • musaddiqmanzoor4
     + 0 comments

    String pattern = "^(([01]?([0-9][0-9]?)|2[0-4][0-9]|25[0-5]?)\.){3}([01]?([0-9][0-9]?)|2[0-4][0-9]|25[0-5]?)$";

  • kumaravel140795
     + 0 comments

    class MyRegex {

       String pat = "(\\b\\d\\b|\\b[1-9][1-9]\\b|\\b[0-1][0-9][0-9]\\b|\\b2[0-4][0-9]\\b|\\b25[0-5]\\b)";
   String pattern = "^"+pat+"\\."+pat+"\\."+pat+"\\."+pat+"$";

    }

  • kushkapoor6707
     + 0 comments

    import java.util.regex.Matcher; import java.util.regex.Pattern; import java.util.Scanner;

    class Solution{

    public static void main(String[] args){
    Scanner in = new Scanner(System.in);
    while(in.hasNext()){
        String IP = in.next();
        System.out.println(IP.matches(new MyRegex().pattern));
    }

}

    } public class MyRegex { public static void main(String[] args) { MyRegex regex = new MyRegex(); Scanner scanner = new Scanner(System.in);

        while (scanner.hasNext()) {
        String ip = scanner.next();
        // Validate the IP against the regex pattern
        System.out.println(ip.matches(new MyRegex().pattern));
    }

    scanner.close();
}

    }

  • ing_urirmz
     + 0 comments
    class MyRegex {
    private String patternFor256 = "([01]?[0-9][0-9]?|2[0-4][0-9]|25[0-5])";
    public String pattern = String.format("%1$s.%1$s.%1$s.%1$s", patternFor256);
}

  • AlphaVolk77
     + 0 comments

    my solution:

    import java.io.*;
import java.util.*;

public class Solution {

        public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        while(sc.hasNext())
        {
            String IP = sc.next();
            System.out.println(IP.matches(new MyRegex().pattern));
        }

    }
}

class MyRegex {

    String pattern = "^(([0-1]?[0-9][0-9]?|2[0-4][0-9]|25[0-5])\\.){3}(([0-1]?[0-9][0-9]?|2[0-4][0-9]|25[0-5]))$";
}