user super keyword

import java.util.*;
import java.io.*;

class BiCycle{
	String define_me(){
		return "a vehicle with pedals.";
	}
}

class MotorCycle extends BiCycle{
	String define_me(){
		return "a cycle with an engine.";
	}
	
	MotorCycle(){
		System.out.println("Hello I am a motorcycle, I am "+ define_me());

		String temp=super.define_me(); 

		System.out.println("My ancestor is a cycle who is "+ temp );
	}
	
}
class Solution{
	public static void main(String []args){
		MotorCycle M=new MotorCycle();
	}
}

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import java.io.; import java.util.;

public class Solution {

public static void main(String[] args) {
  cycle c = new cycle();
  c.print();

  }

}

class Motorcycle{ public void print(){ System.out.println("Hello I am a motorcycle, I am a cycle with an engine.");

};

} class cycle extends Motorcycle{ @Override public void print(){ super.print();

System.out.println("My ancestor is a cycle who is a vehicle with pedals.");

}

}

my code:

import java.io.; import java.util.;

class bicycle { String text(){ return " with pedals.";

}

}

class moto extends bicycle{ String text(){ return " an engine.";

}
moto(){
    System.out.println("Hello I am a motorcycle, I am a cycle with"+ text());
    String ss = super.text();

    System.out.println("My ancestor is a cycle who is a vehicle"+ ss);
}

}

public class Solution {

public static void main(String[] args) {
    moto bi = new moto();

}

}

Method overriding in Java lets a subclass redefine a method from its parent class, allowing for specialized behavior. The super keyword is used to invoke the parent class's method, ensuring the original functionality is preserved alongside the new implementation.

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