Discussion on Java Exception Handling (Try-catch) Challenge

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334 Discussions

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2 days ago+ 0 comments

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
        try (Scanner scanner = new Scanner(System.in)) {
            int x = scanner.nextInt();
            int y = scanner.nextInt();

            System.out.println(x/y);
        } catch (Exception e) {
            System.out.println(getText(e));
        }
    }

    private static String getText(Exception e) {
        return e.toString().contains(": For input") ? e.toString().substring(0, e.toString().indexOf(":")) : e.toString();
    }

}

1 week ago+ 0 comments

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        
        try {
            int numA = sc.nextInt();
            int numB = sc.nextInt();
            
            System.out.println(numA/numB);
            
        } 
        catch (InputMismatchException e) {
            System.out.println("java.util.InputMismatchException");
        }
        catch (Exception e) {
            System.out.println(e);;
        }
    }
}

5 months ago+ 1 comment

public class Solution {

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
      Scanner sc=new Scanner(System.in);

 try{
     int x=sc.nextInt();
     int y=sc.nextInt();
     int c=x/y;
       System.out.println(c);
 }catch(InputMismatchException q){
     System.out.println("java.util.InputMismatchException");
 }
 catch(Exception q){
     System.out.println(q);
 }
}

}

3 months ago+ 1 comment

why cant we take input before the try block?

4 weeks ago+ 0 comments

sc.nextInt() is used to read integers from the input. However, if the user enters something that is not an integer (e.g., a letter, a decimal number, or a string), sc.nextInt() will throw an InputMismatchException.so that's why we are using inside the try block.

5 months ago+ 0 comments

import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
    //STDIN la Standard Input duoc truyen vao tu Scanner(System.in)
    //STDOUT la Standard Output duoc goi ra tu System.out.print()



    Scanner sc = new Scanner(System.in);
    // Try catch luon tu gia tri x,y duoc truyen vao moi lan qua ban phim
    try{
    int x = sc.nextInt();
    int y = sc.nextInt();
    int a = x/y;

    System.out.println(a);
    }

    catch(InputMismatchException e){
        System.out.println("java.util.InputMismatchException");
    }
    catch(ArithmeticException e){
        System.out.println("java.lang.ArithmeticException: / by zero");
    }

}

}

5 months ago+ 0 comments

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        
        Scanner in = new Scanner(System.in);
        
        try{
            int x = in.nextInt();
            int y = in.nextInt();
            if(x>=0 && y>=0)
            System.out.println(x/y);
        }catch(InputMismatchException ee){
            System.out.println("java.util.InputMismatchException");
        }
            catch(Exception e){
            System.out.println(e.toString());
        }
       
        
    }
}

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