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  1. Prepare
  2. Java
  3. Introduction
  4. Java Datatypes
  5. Discussions

Java Datatypes

  • chegginsw
     + 1 comment

    Why is this wrong, when it gives the exact output as the expected? 

    import java.util.*;
import java.io.*;



class Solution{
    public static void main(String []argh)
    {



        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)System.out.println("* byte");
                if(x>=-32768 && x<=32767)System.out.println("*short");
                if(x>=-2147483648 && x<=2147483647)System.out.println("*int");
               System.out.println("* long");
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}