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  1. Prepare
  2. Java
  3. BigNumber
  4. Java BigDecimal
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Java BigDecimal

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  • jhoneder
     + 0 comments
    package introduction.Java_BigDecimal_25;

import java.math.BigDecimal;
import java.util.*;
import java.util.stream.Collectors;
import java.util.stream.IntStream;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine());

        List<String> list = enterData(n, scanner);
        List<BigDecimal >bigList = list.stream().map(BigDecimal::new).collect(Collectors.toList());

        sortedArray(n, bigList, list);
        scanner.close();
        list.forEach(System.out::println);
    }

    private static void sortedArray(int n, List<BigDecimal> bigList, List<String> list) {
        for(int i = 0; i< n -1; i++) {
            for(int j = 0; j< n -1; j++) {
                if(bigList.get(j).compareTo(bigList.get(j+1)) <0 ) {
                    String temp = list.get(j);
                    BigDecimal temp1 = bigList.get(j);
                    list.set(j, list.get(j+1));
                    bigList.set(j, bigList.get(j+1));
                    list.set(j+1, temp);
                    bigList.set(j+1, temp1);

                }
            }

        }
    }

    private static List<String> enterData(int n, Scanner scanner) {
        return IntStream.range(0, n)
                .mapToObj(i -> scanner.nextLine())
                .collect(Collectors.toList());
    }
}

  • sujaldaware7721
     + 0 comments

    import java.math.BigDecimal; import java.util.*; class Solution{ public static void main(String []args){ //Input Scanner sc= new Scanner(System.in); int n=sc.nextInt(); String []s=new String[n+2]; for(int i=0;i 

        //Write your code here
     try {
        BigDecimal A,B;
        int i = 0;
        String temp;
        while(i < n){
            for(int j = 0; j < n-1; j++){
                A = new BigDecimal(s[j]);
                B = new BigDecimal(s[j+1]);
                if(A.compareTo(B) < 0){
                    temp = s[j];
                    s[j] = s[j+1];
                    s[j+1] = temp;

    // System.out.println(s[j]); } } i++; }

        }catch (NullPointerException  | NumberFormatException e){
        System.out.println(e);
    }

    //Output
    for(int i=0;i<n;i++)
    {
        System.out.println(s[i]);
    }
}

    }

  • sidhantsati
     + 0 comments
       //Solution
    BigDecimal a,b;
    for(int i = 0;i<n;i++){
        for(int j=0;j<n-1-i;j++){
            a=new BigDecimal(s[j]);
            b=new BigDecimal(s[j+1]);
            if(a.compareTo(b)<0){    // algorithm of bubble sort
                String temp = s[j];
                s[j]=s[j+1];
                s[j+1]=temp;
            }
        }
    }

  • brunofragomeni
     + 0 comments

    Important hint, the print is already in the lower end of the code. Hope no one wastes so much time like me because I wasn't realizing how my list was duplicating

  • gracelyganta
     + 0 comments
    import java.util.*;
class Solution{

    public static void main(String []args){
        //Input
        Scanner sc= new Scanner(System.in);
        int n=sc.nextInt();
        String []s=new String[n+2];
        for(int i=0;i<n;i++){
            s[i]=sc.next();
        }
          sc.close();

        //Write your code here

for(int i=0;i<n;i++)
{
    //inserting string values to bigdecimal
    BigDecimal First=new BigDecimal(s[i]);
    int index=i;
    for(int j=i+1;j<n;j++)
    {
        //second BigDecimal to compare the first Bigdecimal
        BigDecimal Second=new BigDecimal(s[j]);

        //comparing if First element is greater that second element
        //if the First element is greater than Second element than compareTo() returns 1

        if(Second.compareTo(First)==1){
            First=Second;
            index=j;
        }
    }

    //temporary variable to store s[i] value

        String temp=s[i];
        s[i]=s[index];
        s[index]=temp;
}
      
        //Output
        for(int i=0;i<n;i++)
        {
            System.out.println(s[i]);
        }
    }

}