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  1. Prepare
  2. Java
  3. Data Structures
  4. Java 1D Array
  5. Discussions

Java 1D Array

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274 Discussions

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  • gracelyganta
     + 0 comments
    import java.util.*;

public class Solution {

    public static void main(String[] args) {
       
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        int[] a = new int[n];
     for(int i=0;i<n;i++)
     {
          a[i]=scan.nextInt();
     }
        scan.close();

        // Prints each sequential element in array a
        for (int i = 0; i < a.length; i++) {
            System.out.println(a[i]);
        }
    }
}

  • n4m774r_d
     + 0 comments

    Practicing mapping:

            //java8
        ArrayList<Integer> A = new ArrayList<>();
        while (scan.hasNextInt())A.add(scan.nextInt());
        int[] a = A.stream().mapToInt(i -> i).toArray();

  • gangulavandanar1
     + 0 comments

    In java 8:

    int[] a = new int[n]; for (int i =0; i < n; i++) { a[i] = scan.nextInt(); }

  • mohantymangaraj1
     + 0 comments

    int a[]=new int[n];

        for(int i=0;i<a.length;i++){
    int b=scan.nextInt();
    a[i]=b;
    }

  • gunvanti_sudhir1
     + 0 comments

    int[] a = new int[n]; for(int i = 0; i < n; i++){ a[i] = scan.nextInt(); }

                this works!!