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  1. Prepare
  2. Python
  3. Itertools
  4. itertools.permutations()
  5. Discussions

itertools.permutations()

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902 Discussions

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  • rahulsinghchauh7
     + 0 comments

    from itertools import permutations

    s = input().split() x = s[0] y = int(s[1]) sorted_s = sorted(x)

    for i in range(1,y+1): # for j in permutations(sorted_s,i): # for j in range(len(sorted_s)): # for j in permutations(sorted_s): for j in permutations(sorted_s,i+1): if i>=2: continue print(''.join(j))

  • a00279833
     + 0 comments
    import sys
from itertools import permutations

for line in sys.stdin.readlines():
    m, n = line.split()
    
str = sorted(permutations(m, int(n)))
for i in str:
    print(''.join(i))

  • battula_sriniva1
     + 0 comments

    from itertools import permutations def permutation(): user_input = input() input_list = user_input.split() var1, var2 = input_list[0], int(input_list[1]) k = list(permutations(var1, var2)) new_list = ["".join(i) for i in k] for element in sorted(new_list): print(element) if name == "main": permutation()

  • syahrulmahar92
     + 0 comments

    from itertools import permutations

    def permut(s, k): s.upper() p_val = list(permutations(s, k)) p_val.sort() [print(''.join(x)) for x in p_val]

    space_sep_input = input().split() string = (space_sep_input[0]).upper() k = int(space_sep_input[1]) permut(string, k)

  • wweave42
     + 0 comments

    Easy 3 liner. Could be two lines but that's ugly code lol

    from itertools import permutations
S, k = input().split()
[print(''.join(x)) for x in sorted(permutations(S, int(k)))]