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  1. Prepare
  2. Python
  3. Itertools
  4. itertools.permutations()
  5. Discussions

itertools.permutations()

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941 Discussions

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  • chinnurajula3894
     + 0 comments

    from itertools import permutations

    strings=input().split(" ")

    string=sorted(strings[0])

    k=int(strings[1])

    result=list(permutations(string,k)) for i in result: tup="".join(i) print(tup)

  • ymq093
     + 0 comments

    from itertools import permutations s,k = input().split() print(*["".join(x) for x in list(permutations(sorted(s),int(k)))],sep="\n")

  • lsloan
     + 0 comments

    The shortest code I could think of…

    from itertools import *
s, k = input().split()
print('\n'.join(''.join(p) for p in permutations(sorted(s), int(k))))

  • rohitambasta_ii1
     + 0 comments
    from itertools import permutations

inp = input().split()

possibilities= list(permutations(inp[0], int(inp[1])))
possibilities.sort()

for i in possibilities:
    print(''.join(i))

  • msh_123
     + 0 comments

    from itertools import permutations

    input_list = list(input().split())

    permutation_length = int(input_list[1])

    permutation_list = (list(input_list[0]))

    permutation_list.sort()

    permutation_result = list(permutations(permutation_list,permutation_length)) x = 0 for i in range(len(permutation_result)): print("".join(permutation_result[x])) x+=1